1396. Design Underground System
https://leetcode.com/problems/design-underground-system/
Implement the class
UndergroundSystem
that supports three methods:
1.
checkIn(int id, string stationName, int t)
- A customer with id card equal to
id
, gets in the stationstationName
at timet
. - A customer can only be checked into one place at a time.
2.
checkOut(int id, string stationName, int t)
- A customer with id card equal to
id
, gets out from the stationstationName
at timet
.
3.
getAverageTime(string startStation, string endStation)
- Returns the average time to travel between the
startStation
and theendStation
. - The average time is computed from all the previous traveling from
startStation
toendStation
that happened directly. - Call to
getAverageTime
is always valid.
You can assume all calls to
checkIn
and checkOut
methods are consistent. That is, if a customer gets in at time t1 at some station, then it gets out at time t2 with t2 > t1. All events happen in chronological order.
Example 1:
Input ["UndergroundSystem","checkIn","checkIn","checkIn","checkOut","checkOut","checkOut","getAverageTime","getAverageTime","checkIn","getAverageTime","checkOut","getAverageTime"] [[],[45,"Leyton",3],[32,"Paradise",8],[27,"Leyton",10],[45,"Waterloo",15],[27,"Waterloo",20],[32,"Cambridge",22],["Paradise","Cambridge"],["Leyton","Waterloo"],[10,"Leyton",24],["Leyton","Waterloo"],[10,"Waterloo",38],["Leyton","Waterloo"]] Output [null,null,null,null,null,null,null,14.0,11.0,null,11.0,null,12.0] Explanation UndergroundSystem undergroundSystem = new UndergroundSystem(); undergroundSystem.checkIn(45, "Leyton", 3); undergroundSystem.checkIn(32, "Paradise", 8); undergroundSystem.checkIn(27, "Leyton", 10); undergroundSystem.checkOut(45, "Waterloo", 15); undergroundSystem.checkOut(27, "Waterloo", 20); undergroundSystem.checkOut(32, "Cambridge", 22); undergroundSystem.getAverageTime("Paradise", "Cambridge"); // return 14.0. There was only one travel from "Paradise" (at time 8) to "Cambridge" (at time 22) undergroundSystem.getAverageTime("Leyton", "Waterloo"); // return 11.0. There were two travels from "Leyton" to "Waterloo", a customer with id=45 from time=3 to time=15 and a customer with id=27 from time=10 to time=20. So the average time is ( (15-3) + (20-10) ) / 2 = 11.0 undergroundSystem.checkIn(10, "Leyton", 24); undergroundSystem.getAverageTime("Leyton", "Waterloo"); // return 11.0 undergroundSystem.checkOut(10, "Waterloo", 38); undergroundSystem.getAverageTime("Leyton", "Waterloo"); // return 12.0
Constraints:
- There will be at most
20000
operations. 1 <= id, t <= 10^6
- All strings consist of uppercase, lowercase English letters and digits.
1 <= stationName.length <= 10
- Answers within
10^-5
of the actual value will be accepted as correct.
---
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class UndergroundSystem { | |
Map<String, Map<Integer, Integer>> in; | |
Map<String, Map<Integer, Integer>> out; | |
public UndergroundSystem() { | |
this.in = new HashMap<String, Map<Integer, Integer>>(); | |
this.out = new HashMap<String, Map<Integer, Integer>>(); | |
} | |
public void checkIn(int id, String stationName, int t) { | |
Map<Integer, Integer> checkins = this.in.getOrDefault(stationName, new HashMap<Integer, Integer>()); | |
checkins.put(id, t); | |
this.in.put(stationName, checkins); | |
} | |
public void checkOut(int id, String stationName, int t) { | |
Map<Integer, Integer> checkouts = this.out.getOrDefault(stationName, new HashMap<Integer, Integer>()); | |
checkouts.put(id, t); | |
this.out.put(stationName, checkouts); | |
} | |
public double getAverageTime(String startStation, String endStation) { | |
Map<Integer, Integer> checkins = this.in.get(startStation); | |
Map<Integer, Integer> checkouts = this.out.get(endStation); | |
int inTime = 0, outTime = 0, matches = 0; | |
for (Map.Entry<Integer, Integer> checkin: checkins.entrySet()) { | |
Integer id = checkin.getKey(); | |
if (checkouts.containsKey(id)) { | |
inTime += checkin.getValue(); | |
outTime += checkouts.get(id); | |
matches++; | |
} | |
} | |
return (outTime - inTime) * 1.0 / matches; | |
} | |
} | |
/** | |
* Your UndergroundSystem object will be instantiated and called as such: | |
* UndergroundSystem obj = new UndergroundSystem(); | |
* obj.checkIn(id,stationName,t); | |
* obj.checkOut(id,stationName,t); | |
* double param_3 = obj.getAverageTime(startStation,endStation); | |
*/ |