606. Construct String from Binary Tree
https://leetcode.com/problems/construct-string-from-binary-tree/
Intuition
Normal pre order
Just handle corner cases, Only node.val for leaf nodes + Empty() for null left node
Use StringBuilder to build prefix, and minimize space complexity
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Time - O(N)
Space - O(N)
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You need to construct a string consists of parenthesis and integers from a binary tree with the preorder traversing way.
The null node needs to be represented by empty parenthesis pair "()". And you need to omit all the empty parenthesis pairs that don't affect the one-to-one mapping relationship between the string and the original binary tree.
Example 1:
Input: Binary tree: [1,2,3,4] 1 / \ 2 3 / 4 Output: "1(2(4))(3)" Explanation: Originallay it needs to be "1(2(4)())(3()())", but you need to omit all the unnecessary empty parenthesis pairs. And it will be "1(2(4))(3)".
Example 2:
Input: Binary tree: [1,2,3,null,4] 1 / \ 2 3 \ 4 Output: "1(2()(4))(3)" Explanation: Almost the same as the first example, except we can't omit the first parenthesis pair to break the one-to-one mapping relationship between the input and the output.---
Intuition
Normal pre order
Just handle corner cases, Only node.val for leaf nodes + Empty() for null left node
Use StringBuilder to build prefix, and minimize space complexity
---
Time - O(N)
Space - O(N)
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